问题： A rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) are the coordinates of its bottom-left corner, and (x2, y2) are the coordinates of its top-right corner. Two rectangles overlap if the area of their intersection is positive. To be clear, two rectangles that only touch at the corner or edges do not overlap. Given two (axis-aligned) rectangles, return whether they overlap.
Example 1:
Input: rec1 = [0,0,2,2], rec2 = [1,1,3,3]
Output: true
Example 2:
Input: rec1 = [0,0,1,1], rec2 = [1,0,2,1]
Output: false
Notes:
Both rectangles rec1 and rec2 are lists of 4 integers.
All coordinates in rectangles will be between -10^9 and 10^9.
方法： 先判断垂直线的相对关系，然后再根据水平线的相对关系分情况判断是否有相交，根据不同的逻辑分支输出最终结果。
具体实现：
class RectangleOverlap {
fun isRectangleOverlap(rec1: IntArray, rec2: IntArray): Boolean {
val x1 = rec1[0]
val y1 = rec1[1]
val x2 = rec1[2]
val y2 = rec1[3]
val x3 = rec2[0]
val y3 = rec2[1]
val x4 = rec2[2]
val y4 = rec2[3]
if(x1 >= x3 && x1 < x4) {
if (y1 >= y3 && y1 < y4) {
return true
} else if (y1 >= y4) {
return false
} else {
if (y2 > y3) {
return true
} else {
return false
}
}
} else if (x1 >= x4) {
return false
} else {
if (x2 > x3) {
if (y1 >= y3 && y1 < y4) {
return true
} else if (y1 >= y4) {
return false
} else {
if (y2 > y3) {
return true
} else {
return false
}
}
} else {
return false
}
}
}
}
fun main(args: Array<String>) {
val rectangleOverlap = RectangleOverlap()
println(rectangleOverlap.isRectangleOverlap(intArrayOf(-7,-3,10,5), intArrayOf(-6,-5,5,10)))
}
有问题随时沟通
